Answer:
4y^6
Step-by-step explanation:
Take out the constants:
40y^14/10y^8
= 40/10 * y^14 / y^8
= 4 * y^(14-8)
= 4 * y^6
= 4y^6
Hope this helped you :3
First: the homogeneous solutions: the characteristic equation is4r^2 - 4r - 3 = 0which has roots r = 3/2, -1/2 hence the homogeneous solution isy = c1.exp(-x/2) + c2.exp(3x/2)
next you need the general form for the guess for yp and that isyp = A1cos(2x) + A2sin(2x)
Now substitute that into the equation and solve for A1, A2.
Answer:
Y=(-x/2)-3
Step-by-step explanation:
You have two points:
(0,-3) and (-4,-1)
The formula of line trough two points is:
(Y-y1)/(y2-y1)=(x-x1)/(x2-x1)
So put these two point like (x1,y1) and (x2,y2) you will get
(Y+3)/(-1+3)=(x-0)/(-4-0)
Y+3=2x/(-4)
Y=-x/2-3
Answer:
c)$73
Step-by-step explanation:
You just have to substitute 4 in for h because h stands for how many hows. They're renting it for 4 hours.
2,3,8
2,8,3
3,8,2
3,2,8
8,2,3
8,3,2
6 triangles.
