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andreyandreev [35.5K]
3 years ago
13

Sandy bought 12 7/8 pounds of peaches to make jam. She and her mother ate 0.75 of a pound of the peaches before making the jam.

They used 9 3/8 pounds of the peaches to make the jam. How many pounds of peaches were left over?
SHOW WORK or i'll just take your answer off and let someone else answer -3-
Mathematics
2 answers:
Verizon [17]3 years ago
5 0

Answer: 2.750

Step-by-step explanation:  make 12 7/8 into a decimal then subtract 0.75 to 12.875 than you have 12.125 now you subtract 9. 375 to 12.125 and you have your answer I hope this is right

Vitek1552 [10]3 years ago
4 0
The answer is 2 6/8

Work-
1. Turn .75 into a fraction which is 3/4.
2. Then change the denominator to be common with the other which would make it 6/8.
3. Then make 12 7/8 into a improper fraction which is 103/8 and subtract the 6/8 to get 97/8.
4. Then change 9 3/8 into an improper fraction which is 75/8.
5. Subtract 75/8 from 97/8 to get 22/8.
6. Lastly, change it to a mixed number which would come out to be 2 6/8.
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Sunny_sXe [5.5K]

Steps to solve:

-20 < 4 - 2x

~Subtract 4 to both sides

-24 < -2x

~Divide -2 to both sides

12 > x

Best of Luck!

6 0
3 years ago
Simplify: 7·(a+5)–30 =
postnew [5]

Answer:

7a + 5

Step-by-step explanation:

Distribute using PEMDAS.


7 0
3 years ago
Ali’s wage was increased from 120$ to 132$ per week. find the increase as fraction on its simplest form, as a percentage of the
Anettt [7]
Well the increase is 132/120. Simplify by dividing 12 from the numerator and the denominator, you should get 11/10.
11/10 is also 110%
7 0
3 years ago
There are two drama classesoffered at a middle school. The 8th grade class has 13 fewer students than the 7th grade class. If th
Eddi Din [679]

Answer:

Class 8 has 27 and class 7 has 40

Step-by-step explanation:

8th (r) class has 13 fewer than 7th (x).
x -13 = r

Total for both classes = 67

r + x - 13 = 67
r + x = 80

80 divided by two = 40 (per class)

40 - 13 =  27

4 0
2 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Mkey [24]

For this case, we have to:

By definition, we know:

The domain of f (x) = \sqrt [3] {x} is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

y = \sqrt [3] {x-2} withx = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x+2}with x = 0:\ y = \sqrt [3] {2} is also defined.

f (x) = \sqrt {x}has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative whenx = 0.

While y = \sqrt {x+2} if it is defined for x = 0.

Answer:

y = \sqrt {x-2}

Option b

6 0
3 years ago
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