Ask question

Ask question

All categories

Alenkasestr [34]

4 years ago

10

A file folder box is in the shape of a rectangular prism with a length of 12 inches, a width of 9 inches, and a height of 10 inc

hes. it is open at the top.find the surface area of the folder box

1 answer:

kari74 [83]4 years ago

6 0

Surface area = 12*9 + 2*12*10 + 2*9*10 = 528 in^2 Answer

(its only one 12*9 because it is open at the top)

You might be interested in

Please help!! Pleaseeee

blsea [12.9K]

Answer:

pretty sure its the first and 3rd one sorry if im wrong

Step-by-step explanation:

6 0

3 years ago

Solve for Literal equation for y<br> 5 = 4x+8y

amid [387]

1/8=y is the answer

6 0

3 years ago

The Walker family is selecting a furniture set. A furniture set has a bed, a desk, and a dresser. There are 2 beds, 2 desks, and

finlep [7]

Answer:

They can select total 8 different furniture sets.

Step-by-step explanation:

Here given

The different choice of beds = 2

The different choice of dresser = 2

The different choice of desks = 2

And they need to choose 1 bed, 1 desk , 1 dresser

So, choice available for a desk = 2

Similarly, choice available for dresser = 2

and choice available for bed = 2

HENCE, THE TOTAL CHOICE OF PERMUTATION IS = 2 x 2 x 2 = 8

So they can select their furniture set in 8 different ways.

7 0

3 years ago

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

b)

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

c)

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

d)

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

2)

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

3 years ago

What is Fifteen more than half a number is 9.

BARSIC [14]

So we'll assume the number is x.

So,

15+ $\frac{x}{2}$ = 9.

Now, we solve for x:

$\frac{x}{2}$ = 9-15

$\frac{x}{2}$ = -6

x = -6*2

x = -12

Check work:

15+ $\frac{-12}{2}$ = 9

15+(-6) = 9

15-6 = 9

9 = 9

7 0

3 years ago