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bazaltina [42]
2 years ago
9

Solve the inequality and graph the solution on the line provided. -7x + 8< -6

Mathematics
1 answer:
HACTEHA [7]2 years ago
7 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-7x+8<-6  Equation/Question

Step 2

-7x+8<-6  Simplify

-7x+8<-6

Step 3

-7x+8<-6  Subtract 8

-7x<-14

Step 4

-7x<-14  Divide sides by -7

answer

x>2

Hope this helps

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9/11 - 1/2 in it's simplest form​
Murrr4er [49]

Answer:

7/22

Step-by-step explanation:

Step 1: <u>Define/explain.</u>

To subtract fractions with different denominators, you must first find the least common denominator (LCM).

You can do this by listing the multiples of each denominator.

Step 2: <u>Solve.</u>

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22

22 is the LCM.

Now, we change the fractions to where they both have denominators of 22.

**REMEMBER: WHICHEVER NUMBER YOU MULTIPLY THE DENOMINATOR BY, YOU MULTIPLY IT BY THE NUMERATOR AS WELL!!**

9/11*2/2=18/22

1/2*11/11=11/22

Now, subtract as normal.

18/22-11/22=7/22

7/22 (simplified).

Step 3: <u>Conclude.</u>

Therefore, 9/11 - 1/2 = 7/22.

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Step-by-step explanation:

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2 years ago
Question Help Of 515515 samples of seafood purchased from various kinds of food stores in different regions of a country and gen
Setler79 [48]

Answer:

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

Step-by-step explanation:

Sample size, n = 51

p = 0.62

1 - p = 1 - 0.62 = 0.38

n = 515

Confidence level = 90% = Zcritical at 90% = 1.645

Confidence interval = (p ± margin of error)

Margin of Error = Zcritical * sqrt[(p(1-p))/n]

Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]

Margin of Error = 1.645 * 0.0214

Margin of Error = 0.035203

Lower boundary = (0.62 - 0.035203) = 0.584797

Upper boundary = (0.62 + 0.035203) = 0.655203

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

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3 years ago
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