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den301095 [7]
3 years ago
8

An observer on the top of a lighthouse observes the angles of depression of two ship at anchor to be 75 and 45 respectively. Fin

d the distance between the two ships if the line joining them points to the base of the light house which is 100 meters high. (use tan 15 = 0.27) Answer should be 73 meter.

Mathematics
1 answer:
frozen [14]3 years ago
7 0

Answer:

Distance between two ships = 73 units

Step-by-step explanation:

Note:

tangent = opposite / hypotenuse

Referring to diagram,

Distance of ship A from tower = 100 tan(90-45) = 100 units

Distance of ship B from tower = 100 tan(90-75) = 100 tan (27) = 27 units

Distance between two ships = 100-27 = 73 units

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Which equation is equivalent to the given equation? x^2+16x=22
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Step-by-step explanation:

x+8=±√

​86

​

​​

2 Break down the problem into these 2 equations.

x+8=\sqrt{86}x+8=√

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​

​​

x+8=-\sqrt{86}x+8=−√

​86

​

​​

3 Solve the 1st equation: x+8=\sqrt{86}x+8=√

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​

​​ .

x=\sqrt{86}-8x=√

​86

​

​​ −8

4 Solve the 2nd equation: x+8=-\sqrt{86}x+8=−√

​86

​

​​ .

x=-\sqrt{86}-8x=−√

​86

​

​​ −8

5 Collect all solutions.

x=\sqrt{86}-8,-\sqrt{86}-8x=√

​86

​

​​ −8,−√

​86

​

​​ −8

x

​2

​​ +16x−22=0

2 Use the Quadratic Formula.

x=\frac{-16+2\sqrt{86}}{2},\frac{-16-2\sqrt{86}}{2}x=

​2

​

​−16+2√

​86

​

​​

​​ ,

​2

​

​−16−2√

​86

​

​​

​​

3 Simplify solutions.

x=-8+\sqrt{86},-8-\sqrt{86}x=−8+√

​86

​

​​ ,−8−√

​86

​

​​

6 0
3 years ago
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