Answer:
Step-by-step explanation:
from the picture:
QP = QR
and
QR = RS
so
PQ + RS = QS
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
40 + 10x = 5x - 30
To begin isolating x, subtract 40 from both sides.
40 + 10x - 40 = 5x - 30 - 40
10x = 5x - 70
Subtract 5x from both sides.
10x - 5x= 5x - 70 - 5x
5x = -70
Finally, divide both sides by 5.
5x/5 = -70/5
x = -14
Answer:
x = -14
Answer:
2n -4
Step-by-step explanation:
n+8 + n-12
Combine like terms
n+n+ 8-12
2n -4
Answer:
B
Step-by-step explanation:
The x intercepts are the points on the graph that touch the x axis in this case the 1 and the 5 are spot on.
