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Flauer [41]
2 years ago
6

What is the median number of excused absences?

Mathematics
1 answer:
zalisa [80]2 years ago
3 0

Answer:

3

Step-by-step explanation:

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Find the measurement of the arc
Lapatulllka [165]

Answer:

146°

Step-by-step explanation:

the measure of an arc that sees the core of the circle is equal to the angle its sees.

6 0
2 years ago
Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 pe
Agata [3.3K]

Answer:

1.1 gigabytes

Step-by-step explanation:

Let us represent:

The number of gigabytes = g

Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 per month.

The Equation is given as:

$71.90 = $67.50 + $4 × g

71.90 = 67.50 + 4g

71.90 - 67.50 = 4g

4.4 = 4g

x = 4.4/4

x = 1.1 gigabytes

Therefore, the number of gigabytes of data Owen can use while staying within his budget is 1.1 gigabytes

8 0
2 years ago
Read 2 more answers
Can you help me find the missing value to the nearest hundredth?! <br>cos□= 2/5 <br><br>Thank you ❤
Aleksandr [31]

Answer:

66.42°

Step-by-step explanation:

Given

cos ? = \frac{2}{5} , then

? = cos^{-1} (\frac{2}{5} ) ≈ 66.42° ( to the nearest hundredth )

7 0
3 years ago
Can someone PLEASE help me with this
Mekhanik [1.2K]

Answer:

4.5 u

Step-by-step explanation:

There are many ways to do it, the most easier is this:

Area=(b*h)/2

Area of ABD = (3*3)/2 = 4.5 u

3 0
3 years ago
Read 2 more answers
The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone
ad-work [718]

Answer:

Part 1) The exponential function is equal to y=1,350(0.95)^{x}

Part 2) The population in 2010 was  992\ fish

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

y=a(b)^{x}

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

a=1,350\ fish

b=(100\%-5\%)=95\%=0.95

substitute

y=1,350(0.95)^{x} ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

y=1,350(0.95)^{x}

so

For x=(2010-2004)=6\ years

substitute

y=1,350(0.95)^{6}=992\ fish

7 0
3 years ago
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