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maks197457 [2]
3 years ago
10

Choose one of the factors of x3 − 1331.

Mathematics
2 answers:
Dmitry [639]3 years ago
3 0
Answer A) x-11
Hope this helps!
ad-work [718]3 years ago
3 0

Answer:

<em>The correct option is:   x-11</em>

Step-by-step explanation:

The given expression is:  x^3 -1331

If we <u>factor out 1331</u>, then we will get: 11\times 11\times 11 which is (11)^3

So, the expression becomes:  x^3- 11^3

Now, <u>the formula we need to apply here</u>:  a^3-b^3=(a-b)(a^2+ab+b^2)

Applying the above formula......

x^3-11^3\\ \\ =(x-11)(x^2+11x+11^2)\\ \\ =(x-11)(x^2+11x+121)

So, one of the factors is  x-11

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horsena [70]
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8 0
2 years ago
ANSWER FAST!!!!!!!
Lemur [1.5K]

Answer:

The angle between the 190 ft. side and the 330 ft. side is 57.9^o

Step-by-step explanation:

<u>The Law of Cosines</u>

When we know the value of all sides of a triangle, we can compute all of its interior angles by using the Law of Cosines, which is a generalization of the Pythagoras's theorem. If a,b, and c are the known sides of a triangle and \alpha is the angle formed by sides a and b (opposite to c), then

\displaystyle c^2=a^2+b^2-2ab\ cos\alpha

We'll use the values a=190, b=330, c=280 because we want to compute the angle opposite to c

\displaystyle cos\alpha =\frac{a^2+b^2-c^2}{2ab}

\displaystyle cos\alpha =\frac{190^2+330^2-280^2}{2(190)(330)}

\displaystyle cos\alpha =\frac{36100+108900-78400}{125400}

\displaystyle cos\alpha =\frac{66600}{125400}=0,5311

\displaystyle \alpha= arccos\ 0.5311

\boxed{\displaystyle \alpha= 57.9^o}

5 0
3 years ago
Need help very fast pls
Butoxors [25]
Y = 1x -5


Hope this helps!!!
5 0
3 years ago
Read 2 more answers
Is 10 and 6 a proportional relationship
pashok25 [27]

Answer:

no

Step-by-step explanation:

6 0
2 years ago
What is the answer to this math question please help thank you very much
NeX [460]
All the angles in a triangle= 180 degrees.

2x+5x+3x= 180

Combine like terms.

10x= 180

Divide by 10 into both sides.

x= 18

Now, plug that into <L.

3(18)= <L

<L= 54 degrees

I hope this helps!
~kaikers

5 0
3 years ago
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