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3 years ago

M - 1 = 2 what do I need to do to solve.

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

In order to solve this, start by adding 1 to both sides of the equation.

m-1=2

+1 +1

-----------

m=3

The solution to your equation is 3.

You can also check to see if this is true by replacing m with 3.

m-1=2

3-1=2

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Write in standard form: 22.2 x 10^5

garri49 [273]

2220000

it just means that 22.2 needs to be multiplied by 10, 5 times, so just move the decimal five to the right.

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3 years ago

Mr. Ramirez built a wooden storage shed for his tools. The dimensions of the shed are shown below. What is the volume of the sto

ankoles [38]

Answer:

$Volume = 24\ ft^3$

Step-by-step explanation:

Given [Missing from the question]

$Length = 170cm\\ Width = 100cm\\ Height = 40cm$

Required

Determine the volume

This is calculated as:

$Volume = Length * Width * Height$

$Volume = 170cm * 100cm * 40cm$

$Volume = 680000cm^3$

Convert to cubic foot [Divide by 28317 ]

$Volume = \frac{680000\ ft/^3}{28317}$

$Volume = 24.0138432744\ ft^3$

$Volume = 24\ ft^3$ --- approximated

7 0

3 years ago

which sentence most accurately describes how to solve for perimeter multiplying dividing subtracting or adding all sides of the

saul85 [17]

Answer:

Is there supost to be an image or options orrr?....

Step-by-step explanation:

4 0

3 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

3 years ago

PLEASE ANSWER ASAP!!!!!!!!!!!!!

Licemer1 [7]

Answer:

Since you have to distribute the 4 to both terms in parentheses, the equation is simplified like this:

1 + 12x - 40 -12x

= 1 - 40

= -39

Step-by-step explanation:

7 0

2 years ago

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