Answer:
the first option
Step-by-step explanation:
really, just look at the table.
is the mean value (10.4) larger than the median (13.4) ?
I hope you can see right away that it is not.
and you can see they are not the same either.
so, all the answer options mentioning mean larger than median or equal to median can be ruled out right away.
so, it is between the first two options.
now think ! how do we draw number lines ? a coordinate axis ?
the smaller numbers left, the larger numbers right. the numbers grow from left to right.
the mean value is simply the sum of all measurements divided by the number of measurements (how many median were done). if that is smaller that the median (so, the Mean is left of the Median), it means that the majority of measurements had a result smaller (to the left) than the Median. so, it is skewed-left.
Answer:
<h2>brainiest me</h2>
Step-by-step explanation:
The value returned is TRUE if all of the values in x are TRUE (including if there are no values), and FALSE if at least one of the values in x is FALSE. Otherwise the value is NA (which can only occur if na.rm = FALSE and ... contains no FALSE values and at least one NA value).
1) Call x the sample mean = 3.56
2) Call s the sample standard deviation = 0.2
3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:
x +/- Z(0.5) s/√n
Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.
Z(0.5) = 0.3085
Then the inteval is
x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
