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melamori03 [73]
3 years ago
6

Help me answer me some one please I will do 34 points 2 parts A and B

Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

Given:

Funnel is in the shape of a cone.

Radius = 4 inches

Height = 10 inches

To find:

a) The volume of the funnel

b) How many quarts of oil are in the funnel.

Solution:

Volume of cone:

$V=\frac{1}{3}\pi r^2 h

$V=\frac{1}{3}\times 3.14 \times 4^2 \times 10

$V=167.47 in³

The volume of the funnel is 167.47 in³.

1 qt ≈ 58 in³

To convert cubic inch to quarts divide by 58.

$167.47in^3=\frac{167.47}{58}

               = 2.9 quarts

Therefore 2.9 quarts of oil are in the funnel.

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Answer:

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Simplify fully: X^2+3x-4/ 2x^2-5x+3
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Answer:

(-x - 3) • (x - 1)

Step-by-step explanation:

Step  1  :

           2

Simplify   —

           1

Equation at the end of step  1  :

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Step  2  :

Equation at the end of step  2  :

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Step  3  :

Step  4  :

Pulling out like terms :

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  -x2 - 2x + 3  =   -1 • (x2 + 2x - 3)

Trying to factor by splitting the middle term

4.2     Factoring  x2 + 2x - 3

The first term is,  x2  its coefficient is  1 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   1 • -3 = -3

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is   2 .

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                    x2 - 1x + 3x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-1)

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Step-5 : Add up the four terms of step 4 :

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plz mark me as brainliest :)

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