What is the cubic root of - 250
2 answers:
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Answer:
y = -x + 2
Step-by-step explanation:
The equation of a line in a slope intercept form is given as :
, where m is the gradient and c, y - intercept.
First, let us find the gradient, m of the line that passes through the points, (4,-2) and (-5,7) using the relation ;
By substitution we get
We substitute any of the points and the value of m into y= mx + c to find the value for c.
Adding 4 to both sides.
Hence the equation of the line is :
y = -x +2
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to