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3 years ago

Three ratios equivalent to 11/1

Mathematics

2 answers:

Damm [24]3 years ago

8 0

Answer:

21 2

33 3

44 4

Step-by-step explanation:

think of them as equivalent fractions

Temka [501]3 years ago

4 0

Answer: 22/2, 88/8, and 7062000/642000

Explanation: Notice that the ratio in this problem is written with a fraction bar, so we can find equal ratios in the same way that we find equivalent fractions. In other words, we can simply multiply both the numerator and denominator of 11/1 by the same number.

For example, we can multiply both the numerator and denominator of 11/1 by 2 to get the equal ratio 22/2.

We can also multiply both the numerator and denominator of 11/1 by 8 to get the equal ratio 88/8.

We could also multiply the numerator and denominator of 11/1 by 642,000 to get the equal ratio 7062000/642000.

So the ratio 11/1 is equal to 22/2, 88/8, and 7062000/642000.

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A sector from a radius 4 circle has an area of 8 square feet. Find the perimeter of the sector. Use an exact answer.

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Answer:

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mihalych1998 [28]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

4x - 7 (2 - x) = 3x + 2

juin [17]

Answer:

x=2

Step-by-step explanation:

4x−7(2−x)=3x+2

4x+(−7)(2)+(−7)(−x)=3x+2(Distribute)

4x+−14+7x=3x+2

(4x+7x)+(−14)=3x+2(Combine Like Terms)

11x+−14=3x+2

11x−14=3x+2

Step 2: Subtract 3x from both sides.

11x−14−3x=3x+2−3x

8x−14=2

Step 3: Add 14 to both sides.

8x−14+14=2+14

8x=16

Step 4: Divide both sides by 8.

x=2

3 0

3 years ago

A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the

kramer

Answer:

$18.73ft^3$

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top= $(side)^2=x^2$

Area of one side face= $l\times b=xy$

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box= $V=lbh=x^2y$

Total cost= $9(x^2)+5x^2+4(4xy)=14x^2+16xy$

$204=14x^2+16xy$

$204-14x^2=16xy$

$y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}$

Substitute the values of y

$V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)$

Differentiate w.r.t x

$V'(x)=\frac{1}{8}(102-21x^2)=0$

$V'(x)=0$

$\frac{1}{8}(102-21x^2)=0$

$102-21x^2=0$

$102=21x^2$

$x^2=\frac{102}{21}=4.85$

$x=\sqrt{4.85}=2.2$

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

$V''(x)=\frac{1}{8}(-42x)$

Substitute the value

$V''(2.2)=-\frac{42}{8}(2.2)=-11.55$

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value of x

$y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft$

Greatest volume of box= $x^2y=(2.2)^2\times 3.87=18.73 ft^3$

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3 years ago

Let f(x) = -4x + 7 and g(x) = 2x - 6. Find (fºg)(1). A 23 B 0 C 3 D -4

Anit [1.1K]

Answer:

I will get the function of g (x) and plug it on X in the function of f ( x ) and then later substitute X with 1

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2 years ago