Answer:
70° and 110°
Step-by-step explanation:
It is given that, two parallel lines l and m are intersected by a transversal t.
The interior angles on same side of transversal are (2x−8)° and (3x−7)°.
We need to find the measure of these angles.
We know that, the sum of interior angles of the same side of the transversal is equal to 180°. So,
(2x−8)° + (3x−7)° = 180°
⇒ 5x-15=180°
⇒5x=180°+15
⇒5x=195
⇒x=39
Put x = 39 in (2x−8)°,
(2x−8)° = (2(39)-8)°
=70°
Again put x = 39 in (3x−7)°,
(3x−7)° = (3(39)-7)°
=110°
So, the measure of these angles are 70° and 110°.
Answer:
357
Step-by-step explanation:
A) We replace x = - 5 and u = 3 into -3x^3 -2y^2
and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9
or -3x^3 -2y^2 = 375-18= 357
The answer is 357.
B) Replace h = -2 into h^2-3h+2
we have h^2-3h+2 = (-2)^2 -3*(-2) +2 = 4 +6 + 2= 12
The answer is 12
Have a good day.
Sorry but, there’s nothing attached so I can not help you.
Answer:
Do you still need help with this problem?
Answer:
10
4
Step-by-step explanation:
Purple: This makes two trapezoids. A=(a+b)/2 times h
1st = (4+1)/2 x 1 = 2.5
2nd = (4+1)/2 x 3 = 5/2 x 3 = 2.5x3=7.5
Total = 2.5+7.5=10
Green: if you draw a line down the center, you can divide these into two more manageable triangles. A=1/2bh
1st = 1/2x2x2 = 2
2nd = 1/2x2x2 = 2
Total = 2+2=4
