A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the
1 answer:
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Answer:
Hence the new height is 3 times the original height .(h1=3h)
Step-by-step explanation:
Given:
A cone with has height and base with radius r .
To Find:
What is new height
Solution:
Consider as cone with height h base radius r, and volume v
Here given that only height changes for the cone i.e. r remains the unchanged or same or constant
The volume for a regular cone is given by ,
Here V is directly proportional to h i.ee pie ,3 and r being constant
i.e V/h=constant
V1 and h1 are new dimensions for new cone
V/h=V1/h1
Here V1=3V
So V/h=3V/h1
1/h=3/h1
i.e h1=3h
Hence the height is 3 times the original height .
If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB
Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°
Next, look at ΔADB. ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°
Now look at ΔADC. Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>
Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.
CD = 4 cm (given) so AC = 2(4 cm) = 8 cm
Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>
Lastly, look at ΔBHD. Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.
BD = 12 cm, so HD = = 6 cm
Answer: 6 cm