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3 years ago

What does 10+4+9+3 equal

Mathematics

1 answer:

Usimov [2.4K]3 years ago

8 0

Answer:

26.

Step-by-step explanation:

$10+4=14\\ 14+3=17\\ 17+9=26.$

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Kelly tells you that when variables are in the denominator, the equation one over two plus three over x equals three over four b

liubo4ka [24]

(x/(2x))+((2*3)/(2x))=3/4
(x+6)/2x=3/4
4x+24=6x
24=2x
x=12

8 0

3 years ago

Which step should be performed first when simplifying 25 − (14 − 8) + 3 × 2?

Vanyuwa [196]

Answer:

(14-8)

Step-by-step explanation:

Heres why:

Pedmas

P= Parenthesis

E=Exponents

D=Division

M=Multiplication

A=Addition

S= Subtraction

Do that in order.

7 0

3 years ago

Arithmetic and geometric series -Find the sum of the first 50 terms of the following series, to the nearest integer.

grandymaker [24]

Answer:

Step-by-step explanation:

21-13=8 and 29-21=8

So this is aritmetic series where a₁ = 13, and r = 8

Sum of the first n terms:

$S_n=\dfrac{a_1+a_n}{2}\cdot n=\dfrac{a_1+a_1+(n-1)r}{2}\cdot n=\dfrac{2a_1+(n-1)r}{2}\cdot n\\\\\\S_{50}=\dfrac{2\cdot13+(50-1)\cdot8}{2}\cdot50=(13+49\cdot4)\cdot 50=10,450$

5 0

3 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.