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3 years ago

Find the slope of the line that passes through the points (4,10) and (6,9)

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

3 0

Answer:

-1/2

Step-by-step explanation:

The slope of a line is found by using

m = (y2-y1)/(x2-x1)

= (9-10)/(6-4)

= -1/2

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Write the equation in standard<br> form of the line that has<br> x-intercept 6 and y-intercept -2.

zysi [14]

Answer:

Step-by-step explanation:

<u>Equation of the line in intercept form</u>

The intercept form of the equation of a line is:

$\displaystyle \frac{x}{a}+\frac{y}{b}=1$

Where:

a = x-intercept

b = y-intercept

The standard form of a line is:

Ax + By = C

The given line has a=6 and b=-2, thus:

$\displaystyle \frac{x}{6}+\frac{y}{-2}=1$

Multiplying by 6:

x - 3y = 6

This is the required standard form of the line.

Thus, the standard form of the line is:

x - 3y = 6

8 0

3 years ago

Distributive property for 4 2/5x10?<br><br> Distributive property for 26×2 1/2

Nimfa-mama [501]

4 2/5 x 10 = 4x 10 + 2/5 * 10
40 + 4 = 44

26 x 2 1/2 = 26 x 2 + 26 * 1/2
52 + 13 = 65

5 0

2 years ago

Dafna11 [192]

The approximate length of rail that needs to be replaced is 7.1 ft

<h3>Length of arc</h3>

Since the pool is circular, the approximate length that needs to be replaced is an arc of length, L = Ф/360° × πD where

Ф = central angle of rail section = 27° and
D = diameter of circular pool = 30 ft

<h3>Approximate length of rail</h3>

So, substituting the values of the variables into the equation, we have

L = Ф/360° × πD

L = 27°/360° × π × 30 ft

L = 3/40 × π × 30 ft

L = 3/4 × π × 3 ft

L = 9/4 × π ft

L = 2.25 × π ft

L = 7.07 ft

L ≅ 7.1 ft

So, the approximate length of rail that needs to be replaced is 7.1 ft

Learn more about length of an arc here:

brainly.com/question/8402454

5 0

2 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago

Please helppppppppppppppp

Scilla [17]

The first one is 48% and the second one is 60%

4 0

3 years ago