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vesna_86 [32]
3 years ago
9

91/100 in simplest form

Mathematics
1 answer:
otez555 [7]3 years ago
3 0
91/100 is already in simplest form
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A Lake Tahoe Community College instructor is interested in the mean number of days Lake Tahoe Community College math students ar
Vlad1618 [11]

Answer:

d.

Step-by-step explanation:

Hello!

The population is the set of elements that you are interested in studying. In this example, the instructor wants to know the number of days Lake Tahoe Community College math students are absent from class during a quarter. To do so she will take a random sample of math students and register the number of absences of each student. Each math student is an element of the population.

Then the population is "Lake Tahoe Community College math students"

I hope it helps!

6 0
3 years ago
On a horizontal number line, positive numbers are_____
Bond [772]

Answer:

the horizontal are called x-axis, while the vertical are called y-axis

8 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
Please help me with this graph!
trasher [3.6K]

Answer:

y=4/3x-1

Step-by-step explanation:

5 0
3 years ago
Nicole works Monday through Friday and make $250 for her efforts. How much money does she make per day?
bixtya [17]

Answer:

$50 per day

Step-by-step explanation:

she works five days in week and she gets 250 bucks

250/5=50

5 0
3 years ago
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