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3 years ago

Need help with my homework

Mathematics

1 answer:

Klio2033 [76]3 years ago

4 0

Part A is basically asking you for the GCF (greatest common factor) between 63 and 36. To find this you find all the numbers that can be multiplied to form each number.

36:
1 * 36
2*18
3*12
4*9
6*6

63:
1*63
3*21
9*7

The GCF is 9.
Part B is asking how much the GCF can go into each type of flower.
4 rows of geraniums
7 rows of marigolds

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Find the 9th term geometric sequence 1,1/2,1/2^2

valentinak56 [21]

Answer: $t_9=\dfrac{1}{2^8}$

<u>Step-by-step explanation:</u>

$t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}$

3 0

3 years ago

Hai came someone help I too lazy to do it...

baherus [9]

Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

$\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}$ Transform the Expressions

$\frac{1+1}{4} +\frac{3+3+5+5+5+7}{8}$ Calculate the sum

$\frac{2}{4} +\frac{28}{8}$ Reduce

$\frac{1}{2}+\frac{7}{2}$ Transform the Expression

$\frac{1+7}{2}$ Calculate

$\frac{8}{2}$ Reduce the Fraction

$4$

Please mark brainliest if this helped you :)

3 0

3 years ago

The number of texts per day by students in a class is normally distributed with a

kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation$

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2$

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3$

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4) For x < 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

For x > 100:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5$

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5) For x = 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

Option 5 is incorrect

6) For x = 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5$

Since 1.5 is between 1 and 2, option 6 is correct

5 0

3 years ago

PLEASE HELP IT IS 3:30 AM

Nataly_w [17]

Answer:

The answer is y = -1/3x + 5 !

Step-by-step explanation:

If you observe the line, the y-intercept is 5, from the point in the graph (0,5). From that point, we can see that the rise over run is -1/3. Thus, y = -1/3x + 5.

8 0

3 years ago

The distance traveled by a falling object is directly proportional to the square of the time it takes to fall that far. If the o

Aleks04 [339]

Answer:

400 ft

Step-by-step explanation:

Let the distance traveled = d

Let the time taken = t

d α t^2

d = kt^2

k = d /t^2

When d = 100 and t = 2.5secs

k = 100/ (2.5)^2

k = 16

d = 16t^2

When t = 5secs

d = 16(5)^2

d = 16 * 25

d = 400 ft

4 0

3 years ago