Find the differential equation of the family of tangent lines to the parabola y^2 = 2x
1 answer:
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Answer:
B'(16,14)
Step-by-step explanation:
In square ABCD, A(2,7) C(8,1) D(2,1). First, find the coordinates of the vertex B. From the attached diagram you can see that CD=6 units and is parallel to the x-axis, AD=6 units and is parallel to the y-axis. So, B(8,7).
The origin O is the center of dilation, 2 is the scale factor. The rule of the dilation is
(x,y)→(2x,2y)
Thus,
B(8,7)→B'(16,14) (see attached figure).
