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Triss [41]
4 years ago
10

(-4) ( ) = -20 fill in the blank space

Mathematics
1 answer:
kati45 [8]4 years ago
7 0

Answer:

5 because -20 divided by -4 is 5

Step-by-step explanation:

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8. 6r + 5 = 4 6 - 7y -20 ​
Rudiy27

Answer: r=-7/6y+7/2

Step-by-step explanation:

Step 1: Add -5 to both sides.

6r+5+−5=−7y+26+−5

6r=−7y+21

Step 2: Divide both sides by 6.

6r/6=-7y+21/6

3 0
3 years ago
F(ə) =
barxatty [35]

Answer: To get function g, shift f DOWN by 7 units and to the RIGHT by 2 units

Step-by-step explanation: g(x)= (x-2)^2-7 since they’re both negatives it should be the opposite. An example would be g(x)=(x+3)^2+5, f goes UP for positive by 5 units, left by 3 units.

5 0
2 years ago
Three sides of a fence and an existing wall form a rectangular enclosure. The total length of a fence used for the three sides i
ss7ja [257]
<span>Let the wall's length be y. So the fence parallel is also y.

We form the equation;
2x + y = 240

Now the area A is x*y, which is given as 5500.

We have 2 equations with 2 variables. Solve them and get the answer.

xy = 5500
2x + y = 240

Y = 5500/x

2x + (5500/x) = 240
2x^2 - 240x + 5500 = 0
x^2 - 120x + 2750 = 0
Work out the value(s) of x from above. </span>
5 0
3 years ago
Read 2 more answers
So who said i was not good at math???? me i did lol
marysya [2.9K]

Answer:

I got 10 grade on my 7th iready test

Step-by-step explanation:

Just try your best ;-;

5 0
3 years ago
Read 2 more answers
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
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