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sveticcg [70]
4 years ago
5

The points ​(2​,10​) and ​(minus2​,minus10​) are plotted on the coordinate plane using the equation yequalsatimesx. How can you

use the coordinates to find the value of​ a? Select the correct answer​ below, and fill in the answer box to complete your choice. ​(Type a whole​ number.) A. The value of a is the number that the​ y-values are multiplied by to get to the corresponding​ x-values. So, aequals nothing. B. The value of a is the absolute value of the difference of the​ y-values. So, aequals nothing. C. The value of a is the number that the​ x-values are multiplied by to get to the corresponding​ y-values. So, aequals nothing. D. The value of a is the absolute value of the difference of the​ x-values. So, aequals nothing.
Mathematics
1 answer:
andriy [413]4 years ago
6 0

Answer: The value of a is the number that the​ x-values are multiplied by to get to the corresponding​ y-values. So, a equals 5

We have

y=ax  

so a is clearly the number we multiply by the x values.

Substituting either  points (2,10) and (-2,-10),

10 = a(2)

a = 10/2 = 5

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write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)
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The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is y - 3 = \frac{-7x}{2}+ \frac{21}{4}

<h3><u>Solution:</u></h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

<em><u>The slope "m" of the line is given as:</u></em>

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Here the given points are A(-2,2) and B(5,4)

\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4

m=\frac{4-2}{5-(-2)}=\frac{2}{7}

Thus the slope of line with given points is \frac{2}{7}

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}

The perpendicular bisector will run through the midpoint  of the given points

So let us find the midpoint of A(-2,2) and B(5,4)

<em><u>The midpoint formula for given two points is given as:</u></em>

\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }

m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Substituting the given points A(-2,2) and B(5,4)

m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x - x_1)

\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)

y - 3 = \frac{-7}{2}(x - \frac{3}{2})\\\\y - 3 = \frac{-7x}{2}+ \frac{21}{4}

Thus the equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is found out

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