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horrorfan [7]
3 years ago
14

Select all the equations where z= 5 is a solution. Na

Mathematics
1 answer:
kolezko [41]3 years ago
5 0

Answer: A, D, & E

Step-by-step explanation:

they are all correct when 5 is plugged in.

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I need to know the equations
dem82 [27]
Let l, t, b represent the numbers of lions, tigers, bears, respectively.

2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals

_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
4 0
3 years ago
Read 2 more answers
Suppose you invest $2000 at annual interest rate of 4.5 % How much money do you have in the account after five years?
Naya [18.7K]

Answer:

if my math is correct

Step-by-step explanation:

2501.50

2504.65

5 0
3 years ago
Solve for A ? <br><br> Anyone willing to help me :)
GrogVix [38]

Answer:

<h2>2.2</h2>

Step-by-step explanation:

Use the cosine law:

BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)

We have:

BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848

Substitute:

a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2

5 0
3 years ago
The distribution of cholesterol levels in teenage boys is approximately normal withnbsp mu equals 170 and sigma equals 30 ​(Sour
ddd [48]

Answer: 0.0336

Step-by-step explanation:

Given : The distribution of cholesterol levels in teenage boys is approximately normal with mean :\mu= 170

Standard deviation : \sigma= 30

The formula for z-score is given by :-

z=\dfrac{x-\mu}{\sigma}

For x=225

z=\dfrac{225-170}{30}=1.83

The p-value =P(z>1.83)=1-P(z

=1-0.966375=0.033625\approx0.0336

The probability that a teenage boy has a cholesterol level greater than 225 =0.0336

4 0
3 years ago
At Pike Place Fish Market in Seattle, customers can purchase a variety of different types of seafood. One type of seafood sold a
allsm [11]

Answer:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,0.8)  

Where \mu=3.6 and \sigma=0.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

8 0
3 years ago
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