Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
654 over 3 = divide the both 654 and 3 by 3.
It will give you 218 over 1.
So the answer is 218.
Answer:
n=0
Step-by-step explanation:
Rearrange
10+2=8−2+10
2+10=8−2+10
Combine like terms
2n+10=<u>8n−2n</u>+10
2+10=<u>6</u>+10
Subtract from both sides
2+10=6+10
2+10<u>−10=</u>6+10<u>−10</u>
Simplify
2n=6n
Subtract both sides from 6n of the equation
2=6
2<u>−6</u>=6<u>−6</u>
Solution
n=0
Answer:
hold up im solving it
Step-by-step explanation:
