Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
This answer is 272 I know because I did it vertically
Answer:
(x,y) = -1/2 , 3/2
Step-by-step explanation:
Let y = x +2 ----- (1)
y = -3x ------ (2)
Put equal both sides x +2 = -3x
x = -3x -2
x +3x = -2
4x = -2
x = -1/2 Put it in 2nd equation
Y = -3 (-1/2)
y = 3/2
so (x,y) = -1/2 , 3/2
Hope you got it.
Please Mark as Brainliest.
Steps:
1) determine the domain
2) determine the extreme limits of the function
3) determine critical points (where the derivative is zero)
4) determine the intercepts with the axis
5) do a table
6) put the data on a system of coordinates
7) graph: join the points with the best smooth curve
Solution:
1) domain
The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0
=> x > 3 <-------- domain
2) extreme limits of the function
Limit log (x - 3) when x → ∞ = ∞
Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote
3) critical points
dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)
4) determine the intercepts with the axis
x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4
y-intercept: The function never intercepts the y-axis because x cannot not be 0.
5) do a table
x y = log (x - 3)
limit x → 3+ - ∞
3.000000001 log (3.000000001 -3) = -9
3.0001 log (3.0001 - 3) = - 4
3.1 log (3.1 - 3) = - 1
4 log (4 - 3) = 0
13 log (13 - 3) = 1
103 log (103 - 3) = 10
lim x → ∞ ∞
Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
Answer:
You should evaluate whatever is in the parenthesis first.
