Answer:
48
Step-by-step explanation:
To determine the time it takes for the penny to reach the ground, we use the relation of height and time given above. We do as follows:
<span>
0 =−4.9t^2+(0)t+150
t = sqrt( 150/4.9)
t = 5.53 s
Hope this answers the question. Have a nice day.</span>
2 is the slope so the slope perpendicular to that is -1/2 (negative reciprocal)
-5=-1/2(9) 9*-1/2=-4.5 and -4.5 - 0.5 = -5 so the equation for the line is y=-1/2x -0.5
Answer: -9°F
Step-by-step explanation:
From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.
The temperature, in degrees Fahrenheit, at noon would be:
= -12°F + 1/2(6)
= -12°F + 3°F
= -9°F
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
