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Scilla [17]
2 years ago
15

Which points are 4 units apart?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
3 0

The points that are 4 units apart are B and D

<h3>Complete question</h3>

Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).

B and C

C and D

A and C

B and D

<h3>How to determine the points?</h3>

To do this, we simply calculate the distance using the following equation

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2

Using the given points, we have:

BC = \sqrt{(3+ 1)^2 + (-6 -0)^2} = 7.2

CD = \sqrt{(-1 - 3)^2 + (0 +2)^2} = 4.5

AC = \sqrt{(-2 + 1)^2 + (4 -0)^2} = 4.1

BD = \sqrt{(3 - 3)^2 + (-6 +2)^2} = 4

Hence, the points that are 4 units apart are B and D

Read more about distance at:brainly.com/question/15821277

#SPJ1

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Answer:

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3 years ago
In the standard (x,y) coordinate plane a right triangle has vertices at (-3,4)(3,4)(3,-4) what is the length in coordinates unit
MAXImum [283]

Given:

The vertices of a right triangle are:

(-3,4),(3,4),(3,-4)

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are A(-3,4),B(3,4),C(3,-4).

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(3-(-3))^2+(4-4)^2}

AB=\sqrt{(3+3)^2+(0)^2}

AB=\sqrt{(6)^2+0}

AB=\sqrt{36}

AB=6

Similarly,

BC=\sqrt{(3-3)^2+(-4-4)^2}

BC=\sqrt{(0)^2+(-8)^2}

BC=\sqrt{64}

BC=8

And,

AC=\sqrt{(3-(-3))^2+(-4-4)^2}

AC=\sqrt{(6)^2+(-8)^2}

AC=\sqrt{36+64}

AC=\sqrt{100}

AC=10

Now, taking sum of squares of two smaller sides, we get

AB^2+BC^2=6^2+8^2

AB^2+BC^2=36+64

AB^2+BC^2=100

AB^2+BC^2=AC^2

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

6 0
3 years ago
Expand each logarithm <br> <br>Log (6*11)
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3 years ago
Find the second derivative y= x^2lnx
Dimas [21]
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
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3 0
3 years ago
Please solve, -8-2(7r+1)=-94​
skelet666 [1.2K]

Answer:

r = 6

Step-by-step explanation:

Hello!

-8 - 2(7r + 1) = -94

Add 8 to both sides

-2(7r + 1) = -86

Divide both sides by -2

7r + 1 = 43

Subtract 1 from both sides

7r = 42

Divide both sides by 7

r = 6

Hope this Helps

4 0
3 years ago
Read 2 more answers
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