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4 years ago

3 4/9 as a improper fraction

1 answer:

7 0

First, you do the denominator times he whole number

9 x 3 = 27

Second, you add the total you got to the numerator

27 + 4 = 31

Third, Solve!

31/9 will be your answer

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What is the approximate surface area of the sphere 15yd?

tekilochka [14]

<span>The surface area of a sphere is equal to [4 x Pi x R^2]. In other words, four multiplied by 3.14 multiplied by the radius squared. If the radius of a sphere is 15 yards, the approximate surface area is [4 x 3.14 x (15x15)] = [12.5 x 225] = [2,812 yd^2]. The surface area of a sphere with radius 15 yd is approximately 2,800 yards.</span>

7 0

4 years ago

Find all roots: x^3-7x^2-12x = 0

Pepsi [2]

Answer:

The roots are 0, 3 and 4.

Step-by-step explanation:

x^3-7x^2-12x = 0 Take out x:

x(x^2 - 7x - 12) = 0 Factor the expression in the brackets:

x(x - 3)(x - 4) = 0

x = 0 or x - 3 = 0 or x - 4 = 0, so

The roots are 0, 3 and 4.

5 0

3 years ago

Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet d

Tanzania [10]

I believe it's D
r has to be 1.03

4 0

3 years ago

PLEASE HELP ME I HATE MATH.

dsp73

Answer:

BBBBBBBBBB

Step-by-step explanation:

1/4 mile per 22.5 seconds

7 0

3 years ago

Finding area of shaded sectors.

tekilochka [14]

Answer:

69.81 sq. m. (rounded to 2 decimal places)

Step-by-step explanation:

The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:

$A=\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the central angle

r is the radius

Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:

$\theta = 80$

Also, the radius of the circle shown is 10 meters, so

r = 10

Now, we substitute in formula and find our answer:

$A=\frac{\theta}{360}*\pi r^2\\A=\frac{80}{360}*\pi (10)^2\\A=\frac{2}{9}*100\pi\\A=\frac{200\pi}{9}\\A=69.81$

Thus,

The area of the shaded sector is 69.81 sq. meters.

5 0

3 years ago