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Phantasy [73]
4 years ago
8

3 4/9 as a improper fraction

Mathematics
1 answer:
Annette [7]4 years ago
7 0
First, you do the denominator times he whole number

9 x 3 = 27

Second, you add the total you got to the numerator 

27 + 4 = 31

Third, Solve!

31/9 will be your answer 


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-60x+32=32x-60what is the answer
STatiana [176]

Answer:x=1

Step-by-step explanation:

-60x+32=32x-60

Collect like terms

32x+60x=60+32

92x=92

Divide both sides by 92

92x/92=92/92

x=1

4 0
3 years ago
PLEASE I NEED HELP I GOT A PUPPY AND IM EXHAUSTED HE DOESNT SLEEP AT NIGHT
Luda [366]

Answer:

False

Step-by-step explanation:

It is false because the graph of y=x^{2} does not passes through the point (16,4).

x = 16

y = 4

Substitute

4=16^{2}

4=256

Since 4 is not equal to 256, the answer is false.

4 0
3 years ago
Read 2 more answers
2(3x – 4)= -2(x - 2
vesna_86 [32]

Answer:

2(3x-4)=-2(x-2)

6x-8=-2x+4

6x+2x=4+8

8x=12

x=12/8

x=3/2 or x=1.5

8 0
3 years ago
Read 2 more answers
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
5. A rectangular pool ha a length that is 13 meters longer than its width. perimeter is74 meters. What is the width Its of this
gregori [183]
Good evening Brian,

For this problem, let's look at what we're given.  So we have a pool with a length that is 13 m (meters) longer than its width, and we're given the perimeter, or distance around the entire pool, which is 74 m.

We know that the pool has a rectangular shape and that the perimeter of a rectangle is <span>width + length + width + length ⇒ 2(W) + 2(L)</span>.

Given the information provided, we can rewrite the equation to fit this problem.  Since we're told that the length is equal to 13 m + the width, so we can represent the length as W +13 m.  We can now rewrite the perimeter equation to be:

2(w) + 2 (w + 13 m) ⇒ 2(w) + 2(w) + 2(13 m) ⇒ 4(w) + 26 m = 74 m.

We're down to one variable now so this should be easy.  Subtract 26 m from both sides,

4(w) = 48 m

Now divide each side by 4 in order to find the width.

w = 12 m

-Hope this helps!


6 0
3 years ago
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