All categories

3 years ago

3(x + 5) − 3 = 52 − 2x

2 answers:

7 0

3(x+5)-3=52-2x

1.multiply inside the parentheses by 3 >> {3x+15-3=52-2x}

2. subtract 15 and 2 >>>> {3x+12=52-2x}

3. 3x-2x= 1x >>>> {x+12=52}

4. 52-12= 40 >>> {x=40}

5. answer is 40

Anna11 [10]3 years ago

5 0

Answer: The value of x is 8

Step-by-step explanation:

3(x + 5) − 3 = 52 − 2x

First open the bracket, and do multiplication

3x + 15 - 3 = 52 - 2x

3x + 12 = 52 -2x

Collect like terms, and make the whole expression equal to zero

3x + 12 - (52 - 2x) = 0

3x + 12 - 52 + 2x = 0

3x + 2x + 12 - 52 = 0

5x - 40 = 0

5x = 40

Divide both sides by 5

5x/5 = 40/5

x = 40/5

x = 8

You might be interested in

The volume of the triangular prism is 12.5 m³. The length is 2.5 m and the base is 2 m. What is the width?

Fantom [35]

Answer:

(4) 5 m

Step-by-step explanation:

You want the length of side x of a right triangular prism with base edge lengths of 2.5 m and 2 m, and a volume of 12.5 m³.

<h3>Volume</h3>

The volume of the prism is given by the formula ...

V = Bh

where B is the area of the base:

B = 1/2bh . . . . where b and h are the leg dimensions of the right triangle

Using these formulas together, we have ...

V = 1/2(2.5 m)(2 m)x

12.5 m³ = 2.5x m²

Dividing by 2.5 m², we find x to be ...

(12.5 m³)/(2.5 m²) = x = 5 m

The dimension labeled x has length 5 meters.

6 0

1 year ago

Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

4 years ago

write the equation of the line, in standard form, that is perpendicular to y=3x-2 and passes through (-7,2)

34kurt

Answer:

x+3y=-1

Step-by-step explanation:

y=3x-2 so m=3 old slope

the new slope must be -1/3 (opposite reciprocal of the old slope).

y-y0=m*(x-x0)

y-2=-1/3*(x-(-7))

y-2=-1/3x-1/3*7

y-2=-1/3x-7/3

3y-6=-x-7

The standard form for linear equations in two variables is Ax+By=C.

x+3y=6-7

x+3y=-1

8 0

2 years ago

(a) (x+3)(x+2) =<br><br><br> How do I solve this without the use of parentheses

Ierofanga [76]

Answer: x^2+5x+6

Step-by-step explanation:

5 0

3 years ago

Look across each row of the table. What pattern do you see?

hjlf

Using the same numbers u started out with

7 0

3 years ago

Read 2 more answers