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Anni [7]
3 years ago
9

Elsa had a negative bank account

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer:

it will take her 12 days

Step-by-step explanation:

you do this problem by subtracting the 180 form 720 thne dividing by how much she will be adding every day

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Hi :) I was wondering if you could help, I'm mixed up about this one.​
grigory [225]

Answer:

the image is sideways

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the distance between the points (6, -2) and (9,4)
Alex73 [517]
Distance is 3 sqrt 5
6 0
3 years ago
A.) 170<br> B.) 300<br> C.)280<br> D.)155<br> Please help me
pav-90 [236]

Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

195 + 105 = arcEHF so

arcEHF = 300°

6 0
3 years ago
Round to the nearest tenth if necessary. 60% of 68 is what number?..
galina1969 [7]

Answer:

40.8

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
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