Answer:
<u>One</u>
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25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
w x L = 36
w = L- 5
L x ( L-5 ) = 36
L^2 -5L -36 =0
<span>Use the quadratic formula
L= - b + radical b^2 - 4 (a)(c) divided 2.a
L= 5 + 13 / 2 = 18 /2 =9</span>
Answer:
3x
hope this helps
have a good day :)
Step-by-step explanation:
Answer: 37
Step-by-step explanation:
