Given f(x) = -3x + 1 and g(x) = 4*, find the following combinations:

Mathematics

1 answer:

Nikitich [7]2 years ago

5 0

Step-by-step explanation:

Please refer to the attachment

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Josephine wants to put a wallpaper border around the ceiling of her room. The dimensions are 7 ft and 3 inches and 8 feet and 3

Ilya [14]

Answer:
372inches or 31feet
How to:
7feet and three inches is equal to 87 inches and 8ft and 3 inches is equal to 99 inches. Then you know that both sides have to be multiplied by two because there are four sides in the room. Meaning you have 174in and 198in. Then you add those together to get your answer which is 372. To get back to feet just divide by twelve.

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2 years ago

In a competative exam of 40 questions plus three months is awarded for a correct answer and minus one for every correct answer t

Alex Ar [27]

Answer:

Step-by-step explanation:

n a competitive exam of 40 questions, +3 is awarded for a correct answer and -1 for every wrong answer. Find the total score if a student had 11 wrong answers in his attempt of all questions.

Answers gotten wrong = 11

answers gotten right = 40 - 11 = 29

total score = (point for correct answer x number of correct answer) + (point for wrong answer x number of wrong answer)

(+3 x 29) + (-1 x 11) = 76

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2 years ago

wat factor is paired of 5 to give 45 wat factor is paired with 3 to give 24 wat factor is paired with 6 to give 54

Lady bird [3.3K]

5x9
6x7
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2 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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3 years ago

PLEASE HELP! Which of the following ordered pairs is a solution to the given system of equations?

Paha777 [63]

Answer:

A.............

Step-by-step explanation:

. ..........

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2 years ago

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