Answer:
a. social engineering attack
Explanation:
Two-factor authentication requires that the user/owner of the account enter a second verification code alongside their password in order to access the account. This code is usually sent to a personal phone number or email address. Therefore in order to breach such a security measure the best options is a social engineering attack. These are attacks that are accomplished through human interactions, using psychological manipulation in order to trick the victim into making a mistake or giving away that private information such as the verification code or access to the private email.
Keep the first hard drive then override it insert the second one and memory goes into the second one
Explanation:
The standard punch card (for computers) was invented and developed by Herman Hollerith. But the idea of punch cards was already long invented, used to control Jacquard looms.
Jacquard looms were looms that used punch cards to control the pattern a loom weaves.
The idea of punch cards in Jacquard looms also influenced Charles Babbage, who decided to use punched cards to control the sequence of computations in his proposed analytical engine. Unlike Hollerith's cards of 50 years later, which were handled in decks like playing cards, Babbage's punched cards were to be strung together.
The United Nations currently recognizes 180 currencies that are used in 195 countries across the world the United States dollar is a popular currency and about 66 countries either peg their currency to the US dollar or use it as their currency
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
