Answer:
Explanation:
public class Controlador: MonoBehavior
{
// we declare velocity variable, we can change the value to get more speed
public float velocidad = 3f;
void Start()
{
}
void Update()
{
// with this condition we select the key for the movement.
// for example the left arrow or the letter "a"
if (Input . GetKey(KeyCode . LeftArrow) |I Input . GetKey("a"))
{
transform . position += Vector3 . left * velocidad * Time . deltaTime;
}
if (Input . GetKey(KeyCode . RightArrow) |I Input . GetKey("d"))
{
transform . position += Vector3 . right * velocidad * Time . deltaTime;
}
if (Input . GetKey(KeyCode . UpArrow) |I Input . GetKey("w"))
{
transform . position += Vector3 . up * velocidad * Time . deltaTime;
}
if (Input . GetKey(KeyCode . DownArrow) |I Input . GetKey("s"))
{
transform . position += Vector3 . down * velocidad * Time . deltaTime;
}
}
}
Had to look for the options and here is my answer.
Cydia app is an app that is common found on those devices that are jailbroken because this provides third-party custom apps. Therefore, the presence of Cydia app on an iOS device would indicate that the device has been jailbroken. Hope this helps.
Answer: (B) Migrating all VMs off the host.
Explanation:
VMs migration is the virtual machine migration that basically change the workloads automatically in the system. The maintenance of the schedule results into the downtime in the server for users. In the mission critical environment, when we performing various types of maintenance operation on the host we first require migrate all the virtual machine.
In the critical environment there is a chance that the data in the given host may be critical and the data in the virtual machine (VM) may be in critical position in the host.
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
Answer:
that means it needs to get charged or it's on airplane mode not sure what else it could be
