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lions [1.4K]
3 years ago
13

A chef writing up her famed recipe for beef stew realizes she has switched parsley and oregano everywhere in the recipe. The che

f wants to change all occurrences of “parsley" to “oregano" and all occurrences of “oregano" to “parsley." The chef will use the fact that the word “thyme" does not appear anywhere in the recipe. Which of the following algorithms can be used to fix the chef’s recipe? First, change all occurrences of “parsley" to “oregano." Then, change all occurrences of “oregano" to “parsley." First, change all occurrences of “parsley" to “oregano." Then, change all occurrences of “oregano" to “parsley." Last, change all occurrences of “thyme" to “oregano." First, change all occurrences of “parsley" to “thyme." Then, change all occurrences of “thyme" to “oregano." Last, change all occurrences of “oregano" to “parsley." First, change all occurrences of “parsley" to “thyme." Then, change all occurrences of “oregano" to “parsley." Last, change all occurrences of “thyme" to “oregano."
Computers and Technology
1 answer:
kkurt [141]3 years ago
8 0

Answer:

the last three sentences

Explanation:

first change all of the occurrences of parsley to thyme,

and then all of oregano to parsley

and then all of thyme to oregano

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3 years ago
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In the reaction __H2 + O2 → 2H2O, what coefficient should be placed in front of H2 to balance the reaction?
malfutka [58]
The answer is:  [B]:  " 2 " .
_____________________________________________
Explanation:
____________________________________
Given the chemical equation:
____________________________________

     <u> ? </u> H₂ + O₂ → 2 H₂<span>O   ;
____________________________________________
</span>      → <span> We are asked, "What coefficient, if any — should be put in front of the:  " H</span>₂ " ;
__________________________________________________
          (which is on the "left-hand side" side of the chemical equation given—      the "reactants") ;

     →  to get a balanced chemical equation?
__________________________________________________
 →  Let us examine the "right-hand side" of this chemical equation—the product(s).  In this case, the "product" given is:  " 2 H₂O " .  

So, on the "right hand side", we have:
__________________________________________________
     1)  4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ;  <u><em>and</em></u>:
     2)  2 "O's" → { Two "O's").
__________________________________________________
   So, the left-hand side should have:
__________________________________________________
     1)  4 "H's" ;  <u><em>and</em></u>:
     2)  2 "O's" ;
__________________________________________________
Let us examine the left-hand side (the "reactants").
__________________________________________________
                  " <u> ? </u><u /> H₂  +  O₂ " ; 
__________________________________________________
On the left-hand side, we already have: 
__________________________________________________
     1)   " 2  O's " ;   →  one "O₂" = "2 O's" ;  and:
     2)    "2  H's " ;   →  one "H<span>₂" .</span>

Now, we would need:
__________________________________________________
A "<u>total of "4 H's</u>".  Is there any number we could put as a coefficient on the other reactant, which happens to be:  "H₂" ;  to make a <u><em>total of</em></u> "4 H's" ?          

         {Note: There are only these TWO (2) reactants in this chemical equation.}.  

        → The "H₂" ;  as it stands alone, is insufficient—since that would be only                                                                                         "2 H's".
 __________________________________________________
     →  Thus, we can rule out:  "Answer choices: [A] and [D]."  
___________________________________________________
<u>Note</u>:  
→  Choice [A]:  "1" ;  The coefficient, "1";  is generally not (never?) used; and basically would function as the same as:
          →  Choice: [D]:  "<span>no coefficient is needed".
</span>→  <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
__________________________________________________
Since we are given:  "H</span>₂" ; what coefficient could we put in front of this to get:       "4 H's" ?  (4÷2 =2).  So we could put a "2" in front of the "H₂" ; to get: 
    "4 H's".  The coefficient, "2" , corresponds directly with: 
__________________________________________________
                                             → Answer choice:  [B]:  "2" .
_________________________________________________
   { <u>NOTE</u>:  The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
_________________________________________________
   So, the correctly balanced equation is:

             2 H₂ + O₂ → 2 H₂O  ; 
_________________________________________________
     → The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is:  "2" . 
_________________________________________________
The correct answer is:  [B]:  "2" .  

      → The coefficient that goes before the "H₂" is:  "2" .
_________________________________________________
         Hope this answer—and {lengthy} explanation—is of help!
_________________________________________________
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3 years ago
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7. There are different tools needed in repairing computer, which of the following categories does parts retriever, screw driver,
elena55 [62]

Answer:

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D. Hand tools

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