Answer:
The correct option is option 4 from the options indicated below:
Explanation:
The options are as given below
1-SELECT customer# FROM customers
UNION
SELECT customer# FROM orders;
2-SELECT customer# FROM orders
MINUS
SELECT customer# FROM customers;
3-SELECT customer# FROM orders
INTERSECT
SELECT customer# FROM customers;
4-SELECT customer# FROM customers
MINUS
SELECT customer# FROM orders;
Option 1 is not correct as it will provide the list of all the customers whether they have placed order or not.
Option 2 is not correct as it will provide the list of customers who have placed order but are not in the customers table. This will return the empty records.
Option 3 is not correct as it will provide the list of customers who have placed the order.
Option 4 is correct as it will provide the list of customers from the CUSTOMERS table which are not in the Orders table. thus the list of customers who have not placed the order yet.
B) ask jeanne for permission
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Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
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