I believe it would be 6(10^4)
Try Mäthwáy it works pretty good
Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
Answer: 16
Step-by-step explanation: 80x20=1600
Put the decimal place where it belongs
80% of 20=16
Hope this helps!
Use Order of Operations!! Remember PEMDAS!
P: Parentheses first
E: Exponents (ie Powers and Square Roots, etc.)
MD: Multiplication and Division (left-to-right)
AS: Addition and Subtraction (left-to-right)
7+25•4 (multiply 25 by 4 first)
7+100 (then add 7 to 100)
107
So your final answer would be 107
Hope this helped and I hope you have an awesome day!! :D