<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Answer:
0.3
Step-by-step explanation:
3/10 equals 0.3. Hope this helps :)
The answer is A the perimeter of rectangle A is z times the perimeter of rectangle B
Fist you need to substitute the value of R into the equation
25-6(3)
Now you simply
First multiple 6(3)
25-6(3)
25-18
Now solve!
25-18
7
The answer is 7
ANSWER
EXPLANATION
The given trigonometric equation is
We factor cos(x) to get:
Apply the zero product property to obtain:
Using the unit circle,
when
and
We know
when
The sine function is negative in the third and fourth quadrants.
Hence the solutions are: