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e-lub [12.9K]
3 years ago
14

Jackson goes to the gym 0,2 or 3 days in a week, depending on work demands at the office. The probability that he goes 0 days is

0.1, the probability that he goes 2
days is 0.65, and the probability that he goes 3 days is 0.25. What is the expected value of the number of days per week for which Jackson goes to the gym?
A.
1.55
B.
2.05
C.
2.15
D.
2.50
E.
2.76
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Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
A & ddddddddddddddddddd
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\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

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\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

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\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

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