Ask question

Ask question

All categories

3 years ago

8

NEED HELP ASAP!!! Giving brainliest!!!!!!!

2 answers:

KengaRu [80]3 years ago

5 0

The answer is c I agree with the answers above

attashe74 [19]3 years ago

3 0

C.(f-g)(x) = 4x^3 +5x²-7x-1

Step-by-step explanation:

Given information :

$f(x) = 4 {x}^{3} + 5 {x}^{2} - 3x - 6 \\ g(x) = 4x - 5$

Find :

$(f - g)(x) = \\ (4 {x}^{3} + 5 {x}^{2} - 3x - 6) \\ - 4x -5$

Open bracket and Simplify

$4 {x}^{3} + 5 {x}^{2} - 3x - 6 - 4x + 5 \\ 4 {x}^{3} + 5 {x}^{2} - 7x - 1$

You might be interested in

Please solve <br> 5/5 ÷ 1/2 =

Gala2k [10]

<span>5/5 ÷ 1/2 =
5/5 is the same as 1 so 1/2 of 1 = 1/2
</span>

5 0

3 years ago

A 400 foot rope is extended from the ground to the top of a building. The building is 35 ft tall. What is the angle made by the

velikii [3]

Answer:

The angle is $5.0^{0}$ .

Step-by-step explanation:

The building is 35 feet tall, and the rope is 400 feet long.Applying the trigonometric function, we have;

Sin θ = $\frac{opposite}{hypotenuse}$

The height of the building represents the opposite side, while the length of the rope represents the hypotenuse. Thus;

Sin θ = $\frac{35}{400}$

Sin θ = 0.0875

θ = $Sin^{-1}$ 0.0875

= $5.02^{0}$

The angle made by the rope with respect to the ground is approximately $5.0^{0}$ .

3 0

3 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

3 years ago

Read 2 more answers

HELLPPPPPP PLEASEEE!!!

prisoha [69]

Answer:

Step-by-step explanation:

The first term is 2

Therefor t₁ = 2

Each aditional term is 5 times the previous term

That's the second choice

8 0

3 years ago

Tom's weight = 500 pounds

ruslelena [56]

Answer:

88% of his weight remains

5 0

3 years ago