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Pepsi [2]
3 years ago
12

The area of a circle is πr2. To find the area of a sector with a central angle of Θ, measured in radians, by what should you mul

tiply πr2?
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
There are 2pi radians in a circle

so the fraciton is Θ/(2pi)

so
pir^2 times Θ/(2pi)=pir^2Θ/2pi=Θr^2/2
multiply it by Θ/(2pi)
lora16 [44]3 years ago
6 0

Answer:

\bf\textbf{Area of the sector = }\frac{\theta}{360}\times \pi\times radius^2

Step-by-step explanation:

\text{The area of the circle is }\pi\times radius^2

Now, To find the area of the sector of the circle we must be given the value of the central angle.

In this case, The central angle of the circle is given to be Θ

Now, The measure of one complete angle is 360

So, to find the area of the sector we need to divide the central angle Θ by 360

Hence, the resultant area of the sector of the circle is given by the formula :

\bf\textbf{Area of the sector = }\frac{\theta}{360}\times \pi\times radius^2

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Step-by-step explanation: yep its b

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In each figure a || b. Determine whether the third figure is a translation image of the first figure. Write yes or no. Explain y
harina [27]

Answer:

  No

Step-by-step explanation:

The second and third figures are translations of each other. The first figure appears to be a reflection of the second, not a translation. Hence the first and third figures are not translations of each other.

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If an image is translated, all of the pre-image line segments are parallel to the image line segments. That is not the case for the first and third figures, in which the top line segments go in different directions.

6 0
3 years ago
What is the value of x in the equation 2(6x+4)-6+ 2x = 3(4x+3)+1 ?<br> 1
Salsk061 [2.6K]

Answer:

Here is the process I did:

2(6x+4)-6+2x=3(4x+3)+1

Step 1: Distribute the 2 to the numbers in the parentheses (6x +4) on the left side of the equation

6x(2)+4(2)-6+2x=3(4x+3)+1

12x+8-6+2x=3(4x+3)+1

Step 2: On the left side of the equation combine like terms

x's go with x's (12x and 2x):

(12x + 2x)+8-6=3(4x+3)+1

14x+8-6=3(4x+3)+1

normal numbers go with normal numbers ( 8 and -6):

14x+(8+(-6))=3(4x+3)+1

14x+2=3(4x+3)+1

Step 3: Distribute the 3 to the numbers in the parentheses (4x+3) on the right side of the equation

14x+2=4x(3) +3(3) + 1

14x+2=12x + 9 + 1

Step 4: On the right side of the equation combine like terms

normal numbers go with normal numbers ( 9 and 1):

14x+2=12x + (9 + 1)

14x+2=12x + 10

Step 5: Bring 2 from the left side to the right by subtracting it to both sides

14x+(2-2)=12x + (10-2)

14x = 12x + 8

Step 6: Bring 12x from the right side to the left by subtracting it to both sides

(14x - 12x) = (12x - 12x) + 8

2x = 8

Step 7: Isolate x by dividing 2 to both sides

x = 4

Hope this helped!

8 0
4 years ago
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Alla [95]

Answer:

$8.10

Step-by-step explanation:

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1. 2. 3. total

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3 years ago
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