Answer:
The values of x that make the triangles congruent.
x = 6 and x = 3
Step-by-step explanation:
Given
Given that the triangles are congruent.
According to the SAS (Side-Side-Side)
AC = DC
AB = DB
so
AC = DC
substituting AC = 5x-2 and DC = 3x+10
5x-2 = 3x+10
5x-3x = 10+2
2x = 12
divide both sides by 2
2x/2 = 12/2
x = 6
and
AB = DB
substituting AB = 5x and DB = 4x+3
5x = 4x+3
5x-4x = 3
x = 3
Therefore, the values of x that make the triangles congruent.
x = 6 and x = 3
Let <em>f(x)</em> = (<em>x</em> ² - 1)³. Find the critical points of <em>f</em> in the interval [-1, 2]:
<em>f '(x)</em> = 3 (<em>x</em> ² - 1)² (2<em>x</em>) = 6<em>x</em> (<em>x </em>² - 1)² = 0
6<em>x</em> = 0 <u>or</u> (<em>x</em> ² - 1)² = 0
<em>x</em> = 0 <u>or</u> <em>x</em> ² = 1
<em>x</em> = 0 <u>or</u> <em>x</em> = 1 <u>or</u> <em>x</em> = -1
Check the value of <em>f</em> at each of these critical points, as well as the endpoints of the given domain:
<em>f</em> (-1) = 0
<em>f</em> (0) = -1
<em>f</em> (1) = 0
<em>f</em> (2) = 27
So max{<em>f(x)</em> | -1 ≤ <em>x </em>≤ 2} = 27.
I’m confused on the wording but it might be either 600 or 33.333 (continues forever)
20/29
16/34
40/41
21/20
30/40
21/29
Answer:26/21
Step-by-step explanation:
Total number of students=21
Number of students that plays basket ball=12
Number of students that plays
baseball=14
Number of students that play neither of the games=5
Probability that a student chosen at random plays basket ball or baseball
=12/21+14/21
26/21
