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Fiesta28 [93]
3 years ago
15

If ella babysits from 6:15 to 7:45 and gets paid $12 an hour how much will ella be paid?

Mathematics
1 answer:
sineoko [7]3 years ago
4 0
6:15 to 7:15 = $12 for the hour
7:15 to 7:45 Is a half hour = $6
So total $12 + $6 = $18
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Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of
serious [3.7K]

Answer:

i(x)=12 \times (1+\frac{0.9}{12})^{12x} and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 \times (1.9)^{x}, where x is the number of years.

Since, i(x)=12 \times (1.9)^{x}

i.e. i(x)=12 \times (1+0.9)^{x}.

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}.

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Hence, the monthly growth rate is i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Also, the growth factor is given by \frac{0.9}{12} = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

4 0
3 years ago
An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609
)+618

A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498


A(1.03)\approx 2431.31


Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

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