Answer:
The correct answer is 1.
Step-by-step explanation:
In order to solve the problem
+
, we need can use two methods.
Method 1: Make the denominators the same.
3/9 + 2/3 =
3/9 + 6/9 =
9/9 =
1
Method 2: Turn both fraction into decimals (<em>by dividing the numerator by the denominator</em>.)
3/9 or 3 ÷ 9 = 0.3 (when rounded to the nearest tenth)
2/3 or 2 ÷ 3 = 0.7 (when rounded to the nearest tenth)
0.3 + 0.7 = 1
Therefore, the answer to this question is 1.
(9 x 10 ^(-5)) - (3 x 10^(-16))
Your subtracting to find the difference in size
9 x 10^(-5)
Answer:
29.24 grams
Step-by-step explanation:
It is given that,
Rachel's chocolate bar is 43% cocoa
The weight of the chocolate bar is 68 grams
We need to find how many grams of cocoa does it contain. It means it will contain 43% of 68 grams. It can be solved as follows :

Hence, it will have 29.24 grams of cocoa.

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

TOTAL NUMBER OF ARTICLE= 7
ARTICLES FOR 30K = 3
ARTICLES FOR 12.5K = 7-3= 4

Average cost of 7 articles



