Answer:
10. 3/5
12. 5/6
14. 12/17
15. 2 , 5
18.7
20. 21/22
22. 15
24. 9
26.11,21
Step-by-step explanation:
Answer:
70°
Step-by-step explanation:
∠A =112°,
Exterior angle to angle B is 2x, therefore ∠B = 180 -2x (angle on straight line)
Exterior angle to angle C is 2x + 12, therefore ∠C = 180 -(2x +12) (angle on straight line) = 180 - 12 -2x = 168 - 2x
∠A + ∠B + ∠C = 180 (sum o angles in a triangle)
112 + 180 - 2x + 168 - 2x = 180
460 - 4x = 180
4x = 460 - 180 = 280
x = 280/4 = 70
x = 70°
Answer:
~1.8 mile
Step-by-step explanation:
Michael lives at the closest point to the school (the origin) on Maple Street, which can be represented by the line y = 2x – 4.
This means Michael's house will be the intersection point of line y1 (y = 2x - 4) and line y2 that is perpendicular to y1 and passes the origin.
Denote equation of y2 is y = ax + b,
with a is equal to negative reciprocal of 2 => a = -1/2
y2 pass the origin (0, 0) => b = 0
=> Equation of y2:
y = (-1/2)x
To find location of Michael's house, we get y1 = y2 or:
2x - 4 = (-1/2)x
<=> 4x - 8 = -x
<=> 5x = 8
<=> x = 8/5
=> y = (-1/2)x = (-1/2)(8/5) = -4/5
=> Location of Michael' house: (x, y) = (8/5, -4/5)
Distance from Michael's house to school is:
D = sqrt(x^2 + y^2) = sqrt[(8/5)^2 + (-4/5)^2) = ~1.8 (mile)
Answer:
The length of the loop is approximately 49.58 km.
Step-by-step explanation:
Given:
Time required to ride bicycle in loop = 2 hours and 30 mins
Now we know that;
60 mins = 1 hour
30 mins =0.5 hour
so 2 hour and 30 mins = 
∴ Time required to ride bicycle in loop = 2.5 hrs
Let the speed at which she is riding the bicycle be 's'.
and let Total distance of the loop be 'd'
Now we know that;
Distance is given by speed multiplied by time.
framing in equation form we get;
Now Given:
If she increase the speed by 1 km/hr, it would reduce her time around the loop by 7 minutes.
Hence we can say;
Speed =
Also time will be reduce to 7 mins.
7 mins =0.12 hrs
Now time = 2.5-0.12 =2.38
Again Distance is given by speed multiplied by time.
framing in equation form we get;
Now distance is same for both so we will calculate the speed by equating the equations.
Now Speed = 19.83 km/hr
Length of the loop (d) = 
Hence the length of the loop is approximately 49.58 km.
Answer:
You can say x to the power of 2 or you can say x squared.
Hope that answers your question!
