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Ad libitum [116K]
3 years ago
5

Substitutions y=x+4 y=3x+0

Mathematics
2 answers:
nordsb [41]3 years ago
7 0

Answer:

x= 2

y = 6

Step-by-step explanation:

to solve this system of equation using substitution method,

let

y=x+4............................................................. equation 1

y=3x+0............................................................. equation 1

substitute equation1 into equation 2

we have,

x + 4 = 3x + 0

combine the like terms

4-0 = 3x -x

4 = 2x

divide both sides by the coefficient of x which is 2

4/2 = 2x/2

x = 2

put x = 2 in equation 1

y=x+4............................................................. equation 1

y = 2 + 4

y = 6

therefore the value of x and y are 2 and 6 respectively

cluponka [151]3 years ago
4 0

Answer:

x = 2

Step-by-step explanation:

since both equal y, you can set them equal to each other

x + 4 = 3x + 0

subtract x on both sides

4 = 2x

divide by 2 on both sides

2 = x

♡♡ hope this helped ♡♡

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Answer:

the answer is 918

Step-by-step explanation:

first you would see how many times 257 could go into 28 which is about 9 so you could do 9 times 28 which is 257-252 which is 5. Then bring the 7 down to make 57. Then repeat the first step with every time and you should get 918. (57 goes into 28 once)


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3 years ago
I need to know the answer
Ainat [17]

Answer:

a) 5

b) 20

c) 28

d) 10

Step-by-step explanation:

a) 7-2=5

b) 2(7)+3(2)

= 14+6

= 20

c) 2(7)(3)= 28

d) (7-2)^2

= (14-4)

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3 years ago
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Step-by-step explanation:

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3 years ago
A patient who originally weighed 340 pounds lost 60 pounds. What percent of his original weight did he lose?
Semenov [28]

Answer:

82.35%

Step-by-step explanation:

60 divided by 340=0.17647058823

Multiply that by 100 and you get 17.647058823

Next, round and you get 17.65

100-17.65=82.35

4 0
3 years ago
Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).
marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

A=\frac{3\sqrt{3}}{2} a^2

Where A is the area of the regular hexagon

a is the side length of the regular hexagon

Also, it's Perimeter is given by:

P=6a

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Where d is the distance.

(x_1,y_1) and (x_2,y_2) are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance d)

Applying the above formula we get:

d=\sqrt{(8-4)^2+(0-0)^2} =\sqrt{4^2}=4

\therefore d=4

We know that this distance is the side length of the given regular hexagon.

\therefore d=a=4

Now, if the sides of the given regular polygon are reduced by 40%, then the new length of the sides will be:

a_{small}=4-\frac{40}{100}\times 4=2.4

Thus, the area of the smaller hexagon will be:

A_{small}=\frac{3\sqrt{3}}{2} a_{small}^2=\frac{3\sqrt{3}}{2} (2.4)^2\approx14.96 unit squared

and the new smaller perimeter will be:

P_{small}=6a_{small}=6\times 2.4=14.4 unit

Which are the required answers.

5 0
3 years ago
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