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3 years ago

Simplify: (3x2 - 4x + 6) + (7x - 2)

Mathematics

1 answer:

V125BC [204]3 years ago

8 0

Answer:

11x-2

Step-by-step explanation:

(3x2 - 4x + 6) + (7x - 2) This is the breakdown. (6 4x + 6)= 4x. + (7x-2) = 11x-2

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What is the explicit formula for this sequence?

djyliett [7]

Answer:

C. an= -3+ (n - 115)

Step-by-step explanation:

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2 years ago

amy places adopt on a coordinate plane at (-3,-6) she wants to place another dot across the y-axis and it must be 8 points away.

Vaselesa [24]

(5,-6) because across the y acis meanes the same y Val just a different x Val. and so you could count 8 away from -3 going right. and you'll get my answer

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3 years ago

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What is the volume of the composite figure? Express the

Papessa [141]

Answer:

$V=312\pi\ mm^{3}$

Step-by-step explanation:

we know that

The volume of the composite figure is equal to the volume of a semi-sphere plus the volume of the cone

$V=\frac{4}{6}\pi r^{3} +\frac{1}{3} \pi r^{2} h$

we have

$r=6\ mm$

$h=14\ mm$

substitute

$V=\frac{4}{6}\pi (6)^{3} +\frac{1}{3} \pi (6)^{2} (14)$

$V=144\pi +168\pi$

$V=312\pi\ mm^{3}$

3 0

3 years ago

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I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

3 years ago

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Given: p || q, and r || s.

MariettaO [177]

Answer:

Statement: ∠6 ≅ ∠14

Reason: For parallel lines cut by a transversal, corresponding angles are congruent.

Step-by-step explanation:

In the figure attached, a plot of the problem is shown.

Given p || q and r is a transversal which cut p and q, then ∠1 ≅ ∠5 and ∠2 ≅ ∠6.

Given r || s and q is a transversal which cut r and s, then ∠6 ≅ ∠14 and ∠8 ≅ ∠16.

From the picture we see that ∠1 and ∠2 are supplementary, that is, their addition is equal to 180º. ∠2 ≅ ∠6 and ∠6 ≅ ∠14, then ∠2 ≅ ∠14, in consequence ∠1 and ∠14 are supplementary.

8 0

3 years ago

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