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3 years ago

Write the following in scientific or standard notation:

Mathematics

1 answer:

AURORKA [14]3 years ago

6 0

Answer:

4.879e3 km

Step-by-step explanation:

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6x-5y=17 solve the system

pantera1 [17]

6x-5y=17
-6x -6x
__________
-5y= -6x+17
______________
-5

y=
$\frac{6}{5 } x + \frac{17}{ - 5}$

4 0

3 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

3 years ago

Barry read for 15 more minutes than Robert.

Greeley [361]

Hi!

C. v + 15

Barry read for 15 MORE minutes than Robert.

6 0

3 years ago

A circle is graphed on a coordinate grid. Its center is at (3, 4), and the circle passes through point (3, 1). What is the appro

noname [10]

Answer:

i have the same question

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help me pls!!!!!!!!!

Dominik [7]

Answer:

$x^2+18=-9x : x = -3, x = -6$

Step-by-step explanation:

$x^2+18=-9x$

Add 9x to both sides:

$x^2+18+9x=-9x+9x$

Simplify:

$x^2+9x+18=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3$

$x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6$

The solution to the quadratic equation are:

$x=-3,\:x=-6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0

3 years ago