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gizmo_the_mogwai [7]
3 years ago
13

Change 1.34 repeating into a fraction

Mathematics
1 answer:
cluponka [151]3 years ago
3 0

x=1.\overline{34}\\\\x=1.343434...\qquad|\cdot100\\\\100x=134.343434...\\\\100x-x=134.343434...-1.343434...\\\\99x=133\qquad|:99\\\\x=\dfrac{133}{99}

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What is the product? Enter your answer as a fraction, in simplified form, in the box. 38⋅(−36)
valina [46]
If you multiply 38*(-36) you would get -1368. And to convert that into a fraction it could be -1368/1, -13680/10, etc.
8 0
3 years ago
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Which answer choice shows the number forty-one and three hundredths written in standard form?A. 41.0003 B. 41.003 C. 41.03 D. 41
Harrizon [31]
The right answer is C
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4 years ago
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Extra points// mathematics
timurjin [86]

Answer:

B

Step-by-step explanation:

Givens

a = 2 sqrt(3)

b = 3 sqrt(2)

c = ?

Formula

a^2 + b^2 = c^2

Solution

  • (2sqrt(3))^2 = 2*2 * sqrt(3)*sqrt(3)
  • (2sqrt(3))^2  = 4 * 3
  • (2sqrt(3))^2  = 12
  • (3sqrt(2))^2 = 3 * 3 * sqrt(2)*sqrt(2)
  • (3sqrt(2))^2 = 9 * 2
  • (3sqrt(2))^2 = 18

(2sqrt(3)^2 + 3sqrt(2)^2 ) = c^2

4*3 + 9*2 = c^2

12 + 18 = c^2

c^2 = 30

sqrt(c)^2 = sqrt(30)

c = sqrt(30)

Answer

B

4 0
3 years ago
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Write the system of linear equations <br> Y=3x+1<br> Y=2x+3
Firlakuza [10]

Answer:

x = 2

y =7

Step-by-step explanation:

the system of linear equation will be solve using substitution method,

let

Y=3x+1.............................................. equation 1

Y=2x+3.............................................. equation 2

substitute equation 1 into equation 2

3x + 1 = 2x + 3

combine the like terms

3x+1 -2x = 3

x = 3 -1

x = 2

put the value of x=2 in either equation 1 or 2

Y=2x+3.............................................. equation 2

y = 2(2) + 3

y = 4 + 3

y = 7

7 0
3 years ago
Square root of 22801 by long division method
mezya [45]
First step: partition the number you want to square root into a block of 2 digits, starting from the last digit (first diagram)

Second step: As our number is a five-digits, we ends up with 2  28  01. Pick a number that could be squared to get the first partition, 2. This number is 1, since 1×1=1

Third step: Write 1 on the top and on the side, as shown in the second graph

Fourth step: Double the number on the side, which is 1+1=2 and use this number as the first digit for the next multiplier. Meanwhile, subtract 1 from 2 inside the root sign to get 1, then pull the other two digits, 28

Fifth step: We need a value in the boxes that when we multiply together will give a number less than 128. We choose 5 as 25×5=125

Sixth step: Subtract 125 from  128 to give 3, and as the same concept with long division, bring down the 0 and the 1. So we have 301

Seventh step: Add 5 to the multiplier on the left, so 20+5=30, which we will use on the side as the hundred and ten digits.

Final step: Find a number to fit in the boxes. We choose 1 since 301×1=301

And hence the square root of 228801 is 151

3 0
3 years ago
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