All categories

3 years ago

Please help me b4 11:59 7-1-20

Mathematics

1 answer:

nekit [7.7K]3 years ago

5 0

Answer : The length of QT is 19.

Step-by-step explanation :

As we are given:

Length of RT = 11

Length of RS = 8

As we are given that R is the mid-point of line QS. That means,

Length of RS = Length of QR = 8

Now we have to calculate the length of ST.

Length of ST = Length of RT - Length of RS

Length of ST = 11 - 8

Length of ST = 3

Now we have to calculate the length of QT.

Length of QT = Length of QR + Length of RS + Length of ST

Length of QT = 8 + 8 + 3

Length of QT = 19

Therefore, the length of QT is 19.

You might be interested in

Which of the following expressions has a value of 3? Select all that apply.

Tpy6a [65]

It would be (-1)(-3) :))

7 0

3 years ago

Rentite in simplest terms: - 10(9c – 7c+8) - 80

zhannawk [14.2K]

Answer:

-20c-160

Step-by-step explanation:

-10(9c-7c+8)-80

-10(2c+8)-80

-20c-80-80

-20c-160

8 0

3 years ago

Read 2 more answers

Draw a line say ab take point c out of it through c draw a line parellel to ab using compass and ruler only

nata0808 [166]

Answer:

give me brainliest

Given a line AB with Point C outside it.

Mark point D on the line AB. Join CD

With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.

With C as center, and same radius as before, draw an arc intersecting CD at G.

Open a compass to length EF

Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.

Draw a line m passing through C and H.

Thus m is the line parallel to AB, and passing through point C

∴m∣∣AB

Step-by-step explanation:

4 0

3 years ago

Complete this word<br>[tex] _ r _ch_i_ [\tex]

Anna007 [38]

Answer:

Arachnid is my guess.

3 0

2 years ago

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

3 0

3 years ago