Right Triangle Trigonometry Please Help me with this question:)

yulyashka [42]

Start with

$x-8 > -3$

Add 8 to both sides:

$x > 8-3 \iff x > 5$

4 0

3 years ago

Mashcka [7]

Answer:

yes yes yes yes yes yes yes yes yes yes yes yes yesyes yes yes yes yes yes yes yes yes yes yes yes yes

yes yes yes yes yes yes yes yes yes yes yes yes yes

Step-by-step explanation:

6 0

2 years ago

nalin [4]

Step-by-step explanation:

f(x)+g(x)=(2x^2 + 5x +6) + (3x^2 +4x - 10)

Combine like terms

5x^2 + 9x -4

f(x)-g(x)=(2x^2 + 5x +6) - (3x^2 +4x - 10)

Distribute the negative

(2x^2 + 5x +6) + (-3x^2 -4x + 10)

Combine like terms

-x^2 +x +16

7 0

2 years ago

DerKrebs [107]

x = -4

Have a Merry Christmas!

6 0

2 years ago

Bas_tet [7]

The given plane, $x-y+z=3$ , has normal vector $\vec n = \langle1,-1,1\rangle$ . Any plane parallel to this one has the same normal vector.

Let $(x,y,z)$ be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

$\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle$

and this is perpendicular to $\vec n$ .

So the equation of the plane is

$\langle x-1, y-1, z+1 \rangle \cdot \vec n = 0 \implies (x-1) - (y-1) + (z+1) = 0 \implies \boxed{x - y + z = -1}$

or equivalently,

$\boxed{-x + y - z = 1}$

6 0

1 year ago