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Veronika [31]
2 years ago
5

How many modes does the following data set have?

Mathematics
1 answer:
Andrei [34K]2 years ago
8 0

Answer:

C

Step-by-step explanation:

the mode is the value or values that occur most often in the data set

here 5, 12, 150 all occur 3 times

the mode is then 5, 12, 150

that is there are 3 modes for this data set

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Can someone help me with this and explain it to me please? :)<br><br> CHECK ATTACHED
babymother [125]
23. not equivalent because the first row 3x-9y=5 then if you multiplied this equation by 2 it will be 2(3x-9y) = 2(5) so 6x-18y= 10 not 6x-9y=10


24.equivalent because the second row 2y-6x=8 multiplied by 2 is 2(2y-6x)= 2(8) so 4y-12x=16

25. equivalent because the first row 5x+3y=19 multiplied by 2 is 2(5x+3y) = 2(19) SO 10X+6Y=38 and the second row 2x+4y=20 multiplied by 5 is 5(2x+4y)= 5(20) so 10x+20y=100
4 0
3 years ago
8 books cost 11.20. Find the cost of 5 books
Hunter-Best [27]

First of all we have to find the cost of a book then multiply it by 5 :

$ 11.20 ÷ 8 = $ 1.4

$ 1.4 × 5 = $ 7

Thus 5 books have a cost of $ 7 .

3 0
3 years ago
Read 2 more answers
Solve for the width in the formula for the area of a triangle
zmey [24]

Answer: \frac{2A}{h} = w

Step-by-step explanation:

The formula for area of a triangle is A = wh\frac{1}{2}

Now we have to isolate for w.

First multiply by the 2 which is the reciprocal of 1/2 to cancel it out.

2A = wh\\

Now divide by h to isolate w.

\frac{2A}{h} = w

4 0
3 years ago
A car dealership decreased the price of a certain car by 6%. the original price was $14,600
choli [55]
Well, I am going to assume that your question is asking for the new price of the car after the original price was decreased so here I go...

SOLUTION:

New price = Original price × ( 100% - decrease % )

New price = $14, 600 × ( 100% - 6% )

New price = $ 14, 600 × 94%

New price = $13, 724

Therefore, the answer is:

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6 0
3 years ago
How do I solve this equation quick with an easy method?
Pani-rosa [81]

Answer:

4/(3(x-2))

Step-by-step explanation:

3x^2-21x+30=3(x^2-7x+10)=3(x-5)(x-2)

3x-15=3(x-5)

----------------------------

So the common denominator must be 3(x-5)(x-2)

2(x-2)=2x-4

Add the numerators,

(2x-16)+(2x-4)=4x-16-4=4x-20

-----------------

(4x-20)/[3(x-5)(x-2)]

simplify 4x-20 into 4(x-5)

cancel out the (x-5)'s for both the denominator and the numerator

4/[3(x-2)]

3 0
3 years ago
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