1. Write an expression whose value is the result of converting the str value associated with s to an int value. So if s were ass
ociated with "41" then the resulting int would be 41.2. Write an expression whose value is the last character in the str associated with s.
3. Given variables first and last, each of which is associated with a str, representing a first and a last name, respectively. Write an expression whose value is a str that is a full name of the form "Last, First". So, if first were associated with "alan" and last with "turing", then your expression would be "Turing,Alan". (Note the capitalization! Note: no spaces!) And if first and last were "Florean" and "fortescue" respectively, then your expression’s value would be "Fortescue,Florean".
4. Write an expression whose value is the result of converting the int value associated with x to a str. So if 582 was the int associated with x you would be converting it to the str "582".
5. Write an expression whose value is the str consisting of all the characters (starting with the sixth) of the str associated with s.
3. Given variables first and last, each of which is associated with a str, representing a first and a last name, respectively. Write an expression whose value is a str that is a full name of the form "Last, First". So, if first were associated with "alan" and last with "turing", then your expression would be "Turing,Alan". (Note the capitalization! Note: no spaces!) And if first and last were "Florean" and "fortescue" respectively, then your expression’s value would be "Fortescue,Florean".
4. Write an expression whose value is the result of converting the int value associated with x to a str. So if 582 was the int associated with x you would be converting it to the str "582".
5. Write an expression whose value is the str consisting of all the characters (starting with the sixth) of the str associated with s.
1 answer:
Answer:
The solution or expression for each part is given below:
- int(s)
- s[len(s)-1]
- last.capitalize()+','+first.capitalize()
- str(x)
- s[5:]
Explanation:
Following are attached the images that show how these expressions will be used. I hope they will make the concept clear.
All the images below are respective to the questions given.
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Answer:
The pseudocode is as given below while the flowchart is attached.
Explanation:
The pseudocode is as follows
input customer name, number of texts
Set Basic bill=5 $;
if the number of texts is less than or equal to 60
Extra Charge=0;
If the number of texts is greater than 60 and less than 200
number of texts b/w 60 and 200 =number of texts-60;
Extra Charge=0.1*(number of texts b/w 60 and 200);
else If the number of texts is greater than 200
number of texts beyond 200 =number of texts-200;
Extra Charge=0.25*(number of texts beyond 200)+0.1*(200-60);
Display Customer Name
Total Bill=Basic bill+Extra Charge;
Total Bill after Tax=Total Bill*1.12;
Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// recursive function to print digit of number in revers order
void rev_dig(int num)
{
if(num==0)
return;
else
{
cout<<num%10<<" ";
// recursive call
rev_dig(num/10);
}
}
// driver function
int main()
{
int num;
cout<<"enter a number:";
// read the number from user
cin>>num;
cout<<"digits in revers order: ";
// call the function with number parameter
rev_dig(num);
return 0;
}
Explanation:
Read the input from user and assign it to variable "num". Call the function "rev_dig" with "num" parameter.In this function it will find the last digit as num%10 and print it. Then call the function itself with "num/10". This will print the second last digit. Similarly it will print all the digits in revers order.
Output:
enter a number:1234
digits in revers order: 4 3 2 1
Diagram :
